Five Steps
According to Physics legend Mr. Brian Fudacz, Physics is not math class and should be treated with high intellectual esteem. I don't really give a fuck but if we don't do these five steps we get points docked off on tests.
Steps
- Draw a picture of the scenario
- Identify all variables needed for the Kinematic Equations
- Choose and write down the unmodified equation variation
- Plug and chug for a solution
- Verify that the solution is valid and sensible for the scenario
Example
A model rocket is launched straight upward with an initial speed of 50.0 m/s. It accelerates with a constant upward acceleration of 2.00 m/s^2 until its engines stop at an altitude of 150 m.
- What is the maximum height reached by the rocket?
- How long after lift-off does the rocket reach its maximum height?
- How long is the rocket in the air?
Step 1
Draw shitty pictures in GIMP
Part 1
Part 1 represents when the rocket is being launched into the air.
Part 2
Part 2 represents when the rocket is slowing to its top of decent.
Part 3
Part 3 represents the rocket falling back to earth.
Step 2
Variables
Part 1
- $V_i = 50.0 \text{ m/s}$
- $a = 2.00 \text{ m/s^2}$
- $D = 150 \text{ m}$
- $V_f = \text{ ?}$
- $t = \text{ ?}$
Part 2
Part 3
- $D = 150 + D$3)
- $a = -9.8 \text{ m/s^2}$
- $V_i = 0$
- $t = \text{ ?}$
Answers
- $= D_1 + D_2$
- $= t_2$
- $= t_1 + t_2$
Step 3
Equations
- $V_f^2 = V_i^2 + 2aD$
- $V_f = V_i + at$
- $V_f^2 = V_i^2 + 2aD$ (Part 2)
- $V_f = V_i + at$ (Part 2)
- $D = V_it + \frac{1}{2}at^2$ (Part 3)
Step 4
Equation 1
- $V_f^2 = (50.0)^2 + 2(2.00)(150)$
- $V_f^2 = 2500 + 600$
- $V_f^2 = 3100$
- $\sqrt{V_f^2} = \pm\sqrt{3100}$
- $\boxed{V_f = 55.6 \text{ m/s}}$4)
Equation 2
- $55.6 = 50.0 + 2.00t$
- $5.6 = 2t$
- $\boxed{t = 2.8 \text{ secs}}$
Equation 3
- $0 = (55.6)^2 + 2(-9.8)D$
- $0 = 3091.36 + -19.6D$
- $-3091.36 = -19.6D$
- $\boxed{D = 157.7 \text{ m}}$
Equation 4
- $0 = 55.6 + -9.8t$
- $-55.6 = -9.8t$
- $\boxed{t = 5.7 \text{ secs}}$
Equation 5
- $307.7 = 0t + \frac{1}{2}(9.8)t^2$5)
- $307.7 = 4.9t$
- $\boxed{t = 7.9 \text { secs}}$
Step 5
1)
part 1's answer
2)
gravity
3)
part 2's answer
4)
negative is discarded as it doesn't make sense in context
5)
gravity isn't negative here; in the context of the problem, negative time wouldn't make sense
6)
part 3's D value
7)
sum of the times of part 1 and 2
8)
part 3's answer