Differences

This shows you the differences between two versions of the page.

Link to this comparison view

Both sides previous revisionPrevious revision
Next revision
Previous revision
ap_chem:rate_of_reaction [2021/01/20 05:58] – added bulk of notes epixap_chem:rate_of_reaction [2021/01/21 06:39] (current) – [Integrated Rate Laws] added epix
Line 6: Line 6:
  
 ===== Finding Orders ===== ===== Finding Orders =====
 +{{:ap_chem:2021-01-19-232308_355x199_scrot.png?400  }}
  
-{{:ap_chem:2021-01-19-232308_355x199_scrot.png?400  }}Take the example diagram here for the reaction $2NO_{(g)} + 2H_{2 (g)} -> N_{2 (g)} + 2H_2O_{(g)}$. To determine $m$ and $n$ for the rate law, you have to find pairs of trials that only modify **1** of the reactant compound's quantity, divide it, and compare the quotient to the reaction rate's quotient((as seen in the blue and green markup)) . Refer to the table below for the corresponding order.+Take the example diagram here for the reaction $2NO_{(g)} + 2H_{2 (g)} -> N_{2 (g)} + 2H_2O_{(g)}$. To determine $m$ and $n$ for the rate law, you have to find pairs of trials that only modify **1** of the reactant compound's quantity, divide it, and compare the quotient to the reaction rate's quotient((as seen in the blue and green markup)) . Refer to the table below for the corresponding order.
  
 ^Muliplier^Order^Unit| ^Muliplier^Order^Unit|
Line 37: Line 38:
 Rate of Disappearance is similar to Production, after solving for the production of $N_2$, use [[ap_chem:stoichiometry|stoichiometry]] to find the rate of disappearance. Looking back at our equation, there is a 2:1 ratio of $NO$ to $N_2$, so we'll use that. Rate of Disappearance is similar to Production, after solving for the production of $N_2$, use [[ap_chem:stoichiometry|stoichiometry]] to find the rate of disappearance. Looking back at our equation, there is a 2:1 ratio of $NO$ to $N_2$, so we'll use that.
  
-$ 4 \times 10^{-5} * \frac{2NO}{1N_2} = -8 \times 10^{-5}$ $\frac{\text{mol}}{L}*\text{min}$ which is our rate of disappearance of $NO$ for trial 5.+$ 4 \times 10^{-5} * \frac{2NO}{1N_2} = -8 \times 10^{-5}$ $\frac{\text{mol}}{L}*\text{min}$((the negative is there because it is a rate of disappearance!)) which is our rate of disappearance of $NO$ for trial 5. 
 + 
 +===== Integrated Rate Laws ===== 
 +Use the below chart to determine for each order. Note that half life problems on the AP test will always be given with first order for simplicity. 
 + 
 +{{:ap_chem:5ae8d514bba2df4f1a350329d94c3d8b.jpg?800}}

Navigation

bruh

QR Code
QR Code ap_chem:rate_of_reaction (generated for current page)