Five Steps
According to Physics legend Mr. Brian Fudacz, Physics is not math class and should be treated with high intellectual esteem. I don't really give a fuck but if we don't do these five steps we get points docked off on tests.
Steps
Draw a picture of the scenario
-
Choose and write down the unmodified equation variation
Plug and chug for a solution
Verify that the solution is valid and sensible for the scenario
Example
A model rocket is launched straight upward with an initial speed of 50.0 m/s. It accelerates with a constant upward acceleration of 2.00 m/s^2 until its engines stop at an altitude of 150 m.
What is the maximum height reached by the rocket?
How long after lift-off does the rocket reach its maximum height?
How long is the rocket in the air?
Step 1
Draw shitty pictures in GIMP
Part 1
Part 1 represents when the rocket is being launched into the air.
Part 2
Part 2 represents when the rocket is slowing to its top of decent.
Part 3
Part 3 represents the rocket falling back to earth.
Step 2
Variables
Part 1
$V_i = 50.0 \text{ m/s}$
$a = 2.00 \text{ m/s^2}$
$D = 150 \text{ m}$
$V_f = \text{ ?}$
$t = \text{ ?}$
Part 2
-
$V_f = 0$
$a = -9.8 \text{ m/s^2}$
2)
$D = \text{ ?}$
$t = \text{ ?}$
Part 3
-
$a = -9.8 \text{ m/s^2}$
$V_i = 0$
$t = \text{ ?}$
Answers
$= D_1 + D_2$
$= t_2$
$= t_1 + t_2$
Step 3
Equations
$V_f^2 = V_i^2 + 2aD$
$V_f = V_i + at$
$V_f^2 = V_i^2 + 2aD$ (Part 2)
$V_f = V_i + at$ (Part 2)
$D = V_it + \frac{1}{2}at^2$ (Part 3)
Step 4
Equation 1
$V_f^2 = (50.0)^2 + 2(2.00)(150)$
$V_f^2 = 2500 + 600$
$V_f^2 = 3100$
$\sqrt{V_f^2} = \pm\sqrt{3100}$
$\boxed{V_f = 55.6 \text{ m/s}}$
4)
Equation 2
$55.6 = 50.0 + 2.00t$
$5.6 = 2t$
$\boxed{t = 2.8 \text{ secs}}$
Equation 3
$0 = (55.6)^2 + 2(-9.8)D$
$0 = 3091.36 + -19.6D$
$-3091.36 = -19.6D$
$\boxed{D = 157.7 \text{ m}}$
Equation 4
$0 = 55.6 + -9.8t$
$-55.6 = -9.8t$
$\boxed{t = 5.7 \text{ secs}}$
Equation 5
$307.7 = 0t + \frac{1}{2}(9.8)t^2$
5)
$307.7 = 4.9t$
$\boxed{t = 7.9 \text { secs}}$
Step 5
$\boxed{307.7 \text{ m}} = D$
6) $\checkmark$
$\boxed{8.5 \text{ secs}} = t + t$
7) $\checkmark$
$\boxed{16.4 \text{ secs}} = 8.5 + t$
8) $\checkmark$